Y 5x
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Now in question number eight were asked, which of the following is the graph 2 of this equation, right? And the equation that they give us is Y 3 minus five X is equal to negative six. If you're ever trying to take an equation and turn 7 it into a graph you want to use Y intercept form, 8 which is Y equals MX plus B. Now, 14 if I'm trying to take that minus five X and move it from left 15 to, right, that means I need to add five X to both sides, 16 because that will allow the Xs to cancel on my left, 17 leaving me with just Y and then I'll have a plus five X, 18 which I can just write, um, is five X minus six. So our slope is 21 a positive number.
Y 5x
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If you're seeing this message, it means we're having trouble loading external resources on our website. To log in and use all the features of Khan Academy, please enable JavaScript in your browser. Search for courses, skills, and videos. Intro to slope-intercept form. About About this video Transcript.
Y 5x
If you're seeing this message, it means we're having trouble loading external resources on our website. To log in and use all the features of Khan Academy, please enable JavaScript in your browser. Search for courses, skills, and videos. Solving systems of equations with substitution. The substitution method is a technique for solving a system of equations. This article reviews the technique with multiple examples and some practice problems for you to try on your own. What is the substitution method?
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And the telltale sign of that, when you're doing it algebraically, is you get something wacky like this. So every time we see a y in the second constraint, we can substitute it with that. About About this video Transcript. So these guys cancel out. Posted 11 years ago. So when we go to the second constraint here, every time we see a y, we say, well, the first constraint tells us that y must be equal to negative 5x plus 8. Now, 14 if I'm trying to take that minus five X and move it from left 15 to, right, that means I need to add five X to both sides, 16 because that will allow the Xs to cancel on my left, 17 leaving me with just Y and then I'll have a plus five X, 18 which I can just write, um, is five X minus six. How would you solve this problem? So we can multiply it. And our Y intercept is negative six. Every time you move forward 1, you have to go down 5. It's right over there. So everywhere we see a y, we can substitute it with negative 5x plus 8. So let's do it.
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If a solution exists, it's the point x,y,z at which all three planes intersect. See our results. And the equation that they give us is Y 3 minus five X is equal to negative six. And it's negative 5x plus 8, so 1, 2, 3, 4, 5, 6, 7, 8. This is our y-axis. So let's do it. So negative 5x plus 8 is equal to negative 2. And they give us a system of equations here. So we have 2 times negative 5x is negative 10x. We need a positive slope. So these guys cancel out.
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